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Next: POSIX Regular Expression Syntax Up: Appendix: Regular Expressions Previous: Brief History   Contents

Regular Expressions in Formal Language Theory

Regular expressions consist of constants and operators that denote sets of strings and operations over these sets, respectively. Given a finite alphabet $\Sigma$ the following constants are defined

  • ( empty set ) $\emptyset$ denoting the set $\emptyset$
  • ( empty string ) $\epsilon$ denoting the set $\{ \epsilon \}$
  • ( literal character ) $q \in \Sigma$ denoting the set $\{ q \}$

and the following operations

  • ( concatenation ) $RS$ denoting the set $\{ \alpha \beta \, \vert \, \alpha \in R \, \, and
\, \, \beta \in S \}$. For example, $\{ ab, c \}$ $\{ d, ef \} = \{ abd, abef, cd, cef \}$.
  • ( set union ) $R \cup S$ denoting the set union of $R$ and $S$.
  • ( Keeene star ) $R*$ denoting the smallest superset of $R$ that contains $\epsilon$ and is closed under string concatenation. This is the set of all strings that can be made by concatenating zero or more strings in $R$. For example, $\{ ab, c \}* =
\{ \epsilon, ab, c, abab, abc, cab, cc, ababab, \ldots \}$.

To avoid brackets it is assumed that the Kleene star has the highest priority, then concatenation and then set union. If there is no ambiguity then brackets may be omitted. For example, $(ab)c$ is written as $abc$ and a $\cup \, (b(c*))$ can be written as a $\cup \, bc*$.

Sometimes the complement operator $\sim$ is added; $\sim R$ denotes the set of all strings over $\Sigma$ that are not in $R$. In that case the resulting operators form a Kleene algebra. The complement operator is redundant: it can always be expressed by only using the other operators.

Examples:

  • A $\cup \, b*$ denotes $\{ a, \epsilon, b, bb, bbb, \ldots \}$
  • $(a \cup b)*$ denotes the set of all strings consisting of $a$'s and $b$'s, including the empty string
  • $b*(ab*)*$ the same
  • $ab*(c \cup \epsilon )$ denotes the set of strings starting with $a$, then zero or more $b$'s and finally optionally a $c$.
  • $( bb \cup a(bb)*aa \cup a(bb)*(ab \cup ba)(bb)*(ab \cup ba) )*$ denotes the set of all strings which contain an even number of $b$'s and a number of $a$'s divisible by three.

Regular expressions in this sense can express exactly the class of languages accepted by finite state automata, the regular languages. There is, however, a significant difference in compactness. Some classes of regular languages can only be described by automata that grow exponentially in size, while the required regular expressions only grow linearly. Regular expressions correspond to the type 3 grammars of the Chomsky hierarchy and may be used to describe a regular language.

We can also study expressive power within the formalism. As the example shows, different regular expressions can express the same language, the formalism is redundant.

It is possible to write an algorithm which given two regular expressions decides whether the described languages are equal - essentially, it reduces each expression to a minimal deterministic finite state automaton and determines whether they are equivalent.

To what extent can this redundancy be eliminated? Can we find an interesting subset of regular expressions that is still fully expressive? Kleene star and set union are obviously required, but perhaps we can restrict their use. This turns out to be a surprisingly difficult problem. As simple as the regular expressions are, it turns out there is no method to systematically rewrite them to some normal form. They are not finitely axiomatizable. So, we have to resort to other methods. This leads to the star height problem.


next up previous contents
Next: POSIX Regular Expression Syntax Up: Appendix: Regular Expressions Previous: Brief History   Contents
Andre Merzky 2004-05-13